1、查看当前锁
1.1、pg_locks视图
通过查看pg_locks可以发现授予了哪些锁以及哪些进程正在等待获取锁。查询锁通常使用以下语句:
select relation::regclass, * from pg_locks where not granted;
1.2、pg_stat_activity 视图
结合pg_stat_activity 中的信息,更容易弄清楚哪些进程持有或等待锁。
1.3 阻塞和阻塞活动的组合
以下查询可能有助于查看哪些进程正在阻塞 SQL 语句(这些只能找到行级锁,而不是对象级锁)。
SELECT blocked_locks.pid AS blocked_pid,
blocked_activity.usename AS blocked_user,
blocking_locks.pid AS blocking_pid,
blocking_activity.usename AS blocking_user,
blocked_activity.query AS blocked_statement,
blocking_activity.query AS current_statement_in_blocking_process
FROM pg_catalog.pg_locks blocked_locks
JOIN pg_catalog.pg_stat_activity blocked_activity ON blocked_activity.pid = blocked_locks.pid
JOIN pg_catalog.pg_locks blocking_locks
ON blocking_locks.locktype = blocked_locks.locktype
AND blocking_locks.database IS NOT DISTINCT FROM blocked_locks.database
AND blocking_locks.relation IS NOT DISTINCT FROM blocked_locks.relation
AND blocking_locks.page IS NOT DISTINCT FROM blocked_locks.page
AND blocking_locks.tuple IS NOT DISTINCT FROM blocked_locks.tuple
AND blocking_locks.virtualxid IS NOT DISTINCT FROM blocked_locks.virtualxid
AND blocking_locks.transactionid IS NOT DISTINCT FROM blocked_locks.transactionid
AND blocking_locks.classid IS NOT DISTINCT FROM blocked_locks.classid
AND blocking_locks.objid IS NOT DISTINCT FROM blocked_locks.objid
AND blocking_locks.objsubid IS NOT DISTINCT FROM blocked_locks.objsubid
AND blocking_locks.pid != blocked_locks.pid
JOIN pg_catalog.pg_stat_activity blocking_activity ON blocking_activity.pid = blocking_locks.pid
WHERE NOT blocked_locks.granted;
这是包含 application_name 的相同数据的替代视图
在每个事务的开头设置 application_name 变量可以让您知道哪个逻辑进程阻塞了另一个。它可以是源代码行开始事务的信息,也可以是帮助您将 application_name 与您的代码匹配的任何其他信息。
SET application_name='%your_logical_name%';
SELECT blocked_locks.pid AS blocked_pid,
blocked_activity.usename AS blocked_user,
blocking_locks.pid AS blocking_pid,
blocking_activity.usename AS blocking_user,
blocked_activity.query AS blocked_statement,
blocking_activity.query AS current_statement_in_blocking_process,
blocked_activity.application_name AS blocked_application,
blocking_activity.application_name AS blocking_application
FROM pg_catalog.pg_locks blocked_locks
JOIN pg_catalog.pg_stat_activity blocked_activity ON blocked_activity.pid = blocked_locks.pid
JOIN pg_catalog.pg_locks blocking_locks
ON blocking_locks.locktype = blocked_locks.locktype
AND blocking_locks.DATABASE IS NOT DISTINCT FROM blocked_locks.DATABASE
AND blocking_locks.relation IS NOT DISTINCT FROM blocked_locks.relation
AND blocking_locks.page IS NOT DISTINCT FROM blocked_locks.page
AND blocking_locks.tuple IS NOT DISTINCT FROM blocked_locks.tuple
AND blocking_locks.virtualxid IS NOT DISTINCT FROM blocked_locks.virtualxid
AND blocking_locks.transactionid IS NOT DISTINCT FROM blocked_locks.transactionid
AND blocking_locks.classid IS NOT DISTINCT FROM blocked_locks.classid
AND blocking_locks.objid IS NOT DISTINCT FROM blocked_locks.objid
AND blocking_locks.objsubid IS NOT DISTINCT FROM blocked_locks.objsubid
AND blocking_locks.pid != blocked_locks.pid
JOIN pg_catalog.pg_stat_activity blocking_activity ON blocking_activity.pid = blocking_locks.pid
WHERE NOT blocked_locks.GRANTED;
注意:虽然这个查询大部分都可以正常工作,但它仍然存在一些正确性问题[1],特别是在 9.6 上。
这是相同数据的另一种视图,其中包括状态的执行时间
SELECT a.datname,
l.relation::regclass,
l.transactionid,
l.mode,
l.GRANTED,
a.usename,
a.query,
a.query_start,
age(now(), a.query_start) AS "age",
a.pid
FROM pg_stat_activity a
JOIN pg_locks l ON l.pid = a.pid
ORDER BY a.query_start;
PostgreSQL 9.0以下版本:
select a.datname,
c.relname,
l.transactionid,
l.mode,
l.granted,
a.usename,
a.current_query,
a.query_start,
age(now(), a.query_start) as "age",
a.procpid
from pg_stat_activity a
join pg_locks l on l.pid = a.procpid
join pg_class c on c.oid = l.relation
order by a.query_start;
2、记录日志以供日后分析
如果您怀疑间歇性锁定只是有时导致问题,但在其中一个实时视图中无法捕获它们,那么设置 log_lock_waits和相关的deadlock_timeout参数可能会有所帮助。然后slow lock acquisition会出现在数据库日志中,方便后续分析。
3、其它参考
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